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14052413003 = 56324959881
BaseRepresentation
bin11010001011001011…
…01100111001001011
31100021100002112200212
431011211230321023
5212234404204003
610242223551335
71005142353056
oct150545547113
940240075625
1014052413003
115a61247972
12288215b54b
13142c4306a5
1497443ba9d
15573a37dd8
hex34596ce4b

14052413003 has 4 divisors (see below), whose sum is σ = 14077373448. Its totient is φ = 14027452560.

The previous prime is 14052412999. The next prime is 14052413069. The reversal of 14052413003 is 30031425041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14052413003 - 22 = 14052412999 is a prime.

It is a super-2 number, since 2×140524130032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14052413003.

It is not an unprimeable number, because it can be changed into a prime (14052413093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12479378 + ... + 12480503.

It is an arithmetic number, because the mean of its divisors is an integer number (3519343362).

Almost surely, 214052413003 is an apocalyptic number.

14052413003 is a deficient number, since it is larger than the sum of its proper divisors (24960445).

14052413003 is an equidigital number, since it uses as much as digits as its factorization.

14052413003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24960444.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 14052413003 its reverse (30031425041), we get a palindrome (44083838044).

The spelling of 14052413003 in words is "fourteen billion, fifty-two million, four hundred thirteen thousand, three".

Divisors: 1 563 24959881 14052413003