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14053025353433 = 111277547759403
BaseRepresentation
bin1100110001111111100110…
…0101011000111011011001
31211202110022111111000002112
43030133321211120323121
53320221043442302213
645515512024242105
72650204032412523
oct314377145307331
954673274430075
1014053025353433
1145289444a5530
1216ab6a1910335
137ac26b714221
143682548c4a13
15195841193ea8
hexcc7f9958ed9

14053025353433 has 4 divisors (see below), whose sum is σ = 15330573112848. Its totient is φ = 12775477594020.

The previous prime is 14053025353399. The next prime is 14053025353483. The reversal of 14053025353433 is 33435352035041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14053025353433 - 210 = 14053025352409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14053025353483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638773879691 + ... + 638773879712.

It is an arithmetic number, because the mean of its divisors is an integer number (3832643278212).

Almost surely, 214053025353433 is an apocalyptic number.

It is an amenable number.

14053025353433 is a deficient number, since it is larger than the sum of its proper divisors (1277547759415).

14053025353433 is a wasteful number, since it uses less digits than its factorization.

14053025353433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1277547759414.

The product of its (nonzero) digits is 972000, while the sum is 41.

Adding to 14053025353433 its reverse (33435352035041), we get a palindrome (47488377388474).

The spelling of 14053025353433 in words is "fourteen trillion, fifty-three billion, twenty-five million, three hundred fifty-three thousand, four hundred thirty-three".

Divisors: 1 11 1277547759403 14053025353433