14053230311235 has 16 divisors (see below), whose sum is σ = 22801861013760. Its totient is φ = 7389491994080.

The previous prime is 14053230311221. The next prime is 14053230311251. The reversal of 14053230311235 is 53211303235041.

It is not a de Polignac number, because 14053230311235 - 2⁵ = 14053230311203 is a prime.

It is a super-3 number, since 3×14053230311235³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14053230311196 and 14053230311205.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6597759645 + ... + 6597761774.

It is an arithmetic number, because the mean of its divisors is an integer number (1425116313360).

Almost surely, 2^{14053230311235} is an apocalyptic number.

14053230311235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14053230311235 is a deficient number, since it is larger than the sum of its proper divisors (8748630702525).

14053230311235 is a wasteful number, since it uses less digits than its factorization.

14053230311235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13195521498.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 14053230311235 its reverse (53211303235041), we get a palindrome (67264533546276).

The spelling of 14053230311235 in words is "fourteen trillion, fifty-three billion, two hundred thirty million, three hundred eleven thousand, two hundred thirty-five".