Base | Representation |
---|---|
bin | 11111111101000100100110… |
… | …000100001100010000111001 |
3 | 200102121010122211200012211021 |
4 | 133331010212010030100321 |
5 | 121410021231430303213 |
6 | 1214521245043302441 |
7 | 41413260423036406 |
oct | 3775044604142071 |
9 | 612533584605737 |
10 | 140536263525433 |
11 | 40863104a95076 |
12 | 13918a5237aa21 |
13 | 6055688789119 |
14 | 269bdc47652ad |
15 | 113aa0da87d8d |
hex | 7fd12610c439 |
140536263525433 has 4 divisors (see below), whose sum is σ = 147932908974160. Its totient is φ = 133139618076708.
The previous prime is 140536263525431. The next prime is 140536263525499. The reversal of 140536263525433 is 334525362635041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 140536263525433 - 21 = 140536263525431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140536263525431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3698322724335 + ... + 3698322724372.
It is an arithmetic number, because the mean of its divisors is an integer number (36983227243540).
Almost surely, 2140536263525433 is an apocalyptic number.
It is an amenable number.
140536263525433 is a deficient number, since it is larger than the sum of its proper divisors (7396645448727).
140536263525433 is an equidigital number, since it uses as much as digits as its factorization.
140536263525433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7396645448726.
The product of its (nonzero) digits is 23328000, while the sum is 52.
The spelling of 140536263525433 in words is "one hundred forty trillion, five hundred thirty-six billion, two hundred sixty-three million, five hundred twenty-five thousand, four hundred thirty-three".
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