140544113 has 4 divisors (see below), whose sum is σ = 140848128. Its totient is φ = 140240100.

The previous prime is 140544109. The next prime is 140544133. The reversal of 140544113 is 311445041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311445041 = 311 ⋅1001431.

It is a cyclic number.

It is not a de Polignac number, because 140544113 - 2² = 140544109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140544133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151313 + ... + 152238.

It is an arithmetic number, because the mean of its divisors is an integer number (35212032).

Almost surely, 2^140544113 is an apocalyptic number.

It is an amenable number.

140544113 is a deficient number, since it is larger than the sum of its proper divisors (304015).

140544113 is an equidigital number, since it uses as much as digits as its factorization.

140544113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 304014.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 140544113 is about 11855.1302396895. The cubic root of 140544113 is about 519.9212319053.

Adding to 140544113 its reverse (311445041), we get a palindrome (451989154).

The spelling of 140544113 in words is "one hundred forty million, five hundred forty-four thousand, one hundred thirteen".