Base | Representation |
---|---|
bin | 1100110010000101010010… |
… | …0010110011011111000011 |
3 | 1211202121020212000022202221 |
4 | 3030201110202303133003 |
5 | 3320232210124334220 |
6 | 45520323300551511 |
7 | 2650256612542135 |
oct | 314412442633703 |
9 | 54677225008687 |
10 | 14054551402435 |
11 | 4529557957755 |
12 | 16aba489b2597 |
13 | 7ac452926cbb |
14 | 36835b449055 |
15 | 1958d01369aa |
hex | cc8548b37c3 |
14054551402435 has 8 divisors (see below), whose sum is σ = 17409508834176. Its totient is φ = 10880943021120.
The previous prime is 14054551402393. The next prime is 14054551402453. The reversal of 14054551402435 is 53420415545041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14054551402435 - 29 = 14054551401923 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14054551402391 and 14054551402400.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45337262434 + ... + 45337262743.
It is an arithmetic number, because the mean of its divisors is an integer number (2176188604272).
Almost surely, 214054551402435 is an apocalyptic number.
14054551402435 is a deficient number, since it is larger than the sum of its proper divisors (3354957431741).
14054551402435 is an equidigital number, since it uses as much as digits as its factorization.
14054551402435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90674525213.
The product of its (nonzero) digits is 960000, while the sum is 43.
Adding to 14054551402435 its reverse (53420415545041), we get a palindrome (67474966947476).
The spelling of 14054551402435 in words is "fourteen trillion, fifty-four billion, five hundred fifty-one million, four hundred two thousand, four hundred thirty-five".
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