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14055014012003 = 54125979693183
BaseRepresentation
bin1100110010000111000000…
…0111100001010001100011
31211202122110002111022210122
43030201300013201101203
53320234132041341003
645520441224150455
72650304230630106
oct314416007412143
954678402438718
1014055014012003
114529774aa6108
1216abb5790842b
137ac4c771a283
143683a2a6a73d
1519590aa66238
hexcc8701e1463

14055014012003 has 4 divisors (see below), whose sum is σ = 14080993705728. Its totient is φ = 14029034318280.

The previous prime is 14055014011967. The next prime is 14055014012021. The reversal of 14055014012003 is 30021041055041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14055014012003 - 26 = 14055014011939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14055014017003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12989846051 + ... + 12989847132.

It is an arithmetic number, because the mean of its divisors is an integer number (3520248426432).

Almost surely, 214055014012003 is an apocalyptic number.

14055014012003 is a deficient number, since it is larger than the sum of its proper divisors (25979693725).

14055014012003 is an equidigital number, since it uses as much as digits as its factorization.

14055014012003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25979693724.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 14055014012003 its reverse (30021041055041), we get a palindrome (44076055067044).

The spelling of 14055014012003 in words is "fourteen trillion, fifty-five billion, fourteen million, twelve thousand, three".

Divisors: 1 541 25979693183 14055014012003