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14055053513001 = 319212977888747
BaseRepresentation
bin1100110010000111001001…
…1110001101000100101001
31211202122112211211011222120
43030201302132031010221
53320234222144404001
645520445154541453
72650305220446264
oct314416236150451
954678484734876
1014055053513001
114529795325866
1216abb68b97889
137ac50296a947
143683a7dcdcdb
1519590e26a236
hexcc87278d129

14055053513001 has 12 divisors (see below), whose sum is σ = 19778302451952. Its totient is φ = 8876875902264.

The previous prime is 14055053512949. The next prime is 14055053513003. The reversal of 14055053513001 is 10031535055041.

It is not a de Polignac number, because 14055053513001 - 213 = 14055053504809 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14055053513003) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6488943291 + ... + 6488945456.

It is an arithmetic number, because the mean of its divisors is an integer number (1648191870996).

Almost surely, 214055053513001 is an apocalyptic number.

It is an amenable number.

14055053513001 is a deficient number, since it is larger than the sum of its proper divisors (5723248938951).

14055053513001 is a wasteful number, since it uses less digits than its factorization.

14055053513001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12977888788 (or 12977888769 counting only the distinct ones).

The product of its (nonzero) digits is 22500, while the sum is 33.

Adding to 14055053513001 its reverse (10031535055041), we get a palindrome (24086588568042).

The spelling of 14055053513001 in words is "fourteen trillion, fifty-five billion, fifty-three million, five hundred thirteen thousand, one".

Divisors: 1 3 19 57 361 1083 12977888747 38933666241 246579886193 739739658579 4685017837667 14055053513001