Base | Representation |
---|---|
bin | 1100110010000111110111… |
… | …0110100000100000000011 |
3 | 1211202200001011001221112212 |
4 | 3030201331312200200003 |
5 | 3320240120033332121 |
6 | 45520520135012335 |
7 | 2650313026316456 |
oct | 314417566404003 |
9 | 54680034057485 |
10 | 14055244433411 |
11 | 4529883077125 |
12 | 16b0000b0a0ab |
13 | 7ac5333962bc |
14 | 3683c54cb49d |
15 | 195920dce25b |
hex | cc87dda0803 |
14055244433411 has 4 divisors (see below), whose sum is σ = 14055570455712. Its totient is φ = 14054918411112.
The previous prime is 14055244433383. The next prime is 14055244433479. The reversal of 14055244433411 is 11433444255041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14055244433411 - 222 = 14055240239107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14055249433411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162946475 + ... + 163032708.
It is an arithmetic number, because the mean of its divisors is an integer number (3513892613928).
Almost surely, 214055244433411 is an apocalyptic number.
14055244433411 is a deficient number, since it is larger than the sum of its proper divisors (326022301).
14055244433411 is an equidigital number, since it uses as much as digits as its factorization.
14055244433411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 326022300.
The product of its (nonzero) digits is 460800, while the sum is 41.
Adding to 14055244433411 its reverse (11433444255041), we get a palindrome (25488688688452).
The spelling of 14055244433411 in words is "fourteen trillion, fifty-five billion, two hundred forty-four million, four hundred thirty-three thousand, four hundred eleven".
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