Base | Representation |
---|---|
bin | 1100110010101100011001… |
… | …1111001111010110110011 |
3 | 1211210121100201122000120210 |
4 | 3030223012133033112303 |
5 | 3320420212032131420 |
6 | 45525221322435203 |
7 | 2651111060645001 |
oct | 314530637172663 |
9 | 54717321560523 |
10 | 14065053005235 |
11 | 4532a56823331 |
12 | 16b1a99962b03 |
13 | 7b043750ac5b |
14 | 368a7605da71 |
15 | 195ce70779e0 |
hex | ccac67cf5b3 |
14065053005235 has 8 divisors (see below), whose sum is σ = 22504084808400. Its totient is φ = 7501361602784.
The previous prime is 14065053005207. The next prime is 14065053005281. The reversal of 14065053005235 is 53250035056041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14065053005235 - 25 = 14065053005203 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14065053005193 and 14065053005202.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 468835100160 + ... + 468835100189.
It is an arithmetic number, because the mean of its divisors is an integer number (2813010601050).
Almost surely, 214065053005235 is an apocalyptic number.
14065053005235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14065053005235 is a deficient number, since it is larger than the sum of its proper divisors (8439031803165).
14065053005235 is an equidigital number, since it uses as much as digits as its factorization.
14065053005235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 937670200357.
The product of its (nonzero) digits is 270000, while the sum is 39.
The spelling of 14065053005235 in words is "fourteen trillion, sixty-five billion, fifty-three million, five thousand, two hundred thirty-five".
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