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141000955555 = 528200191111
BaseRepresentation
bin1000001101010001001…
…1111101011010100011
3111110221121011200122011
42003110103331122203
54302232221034210
6144435215453351
713121064230035
oct2032423753243
9443847150564
10141000955555
11548863aa939
12233b0b27257
13103b10750a5
146b78547c55
153a03a40d8a
hex20d44fd6a3

141000955555 has 4 divisors (see below), whose sum is σ = 169201146672. Its totient is φ = 112800764440.

The previous prime is 141000955493. The next prime is 141000955597. The reversal of 141000955555 is 555559000141.

141000955555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 141000955555 - 225 = 140967401123 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14100095551 + ... + 14100095560.

It is an arithmetic number, because the mean of its divisors is an integer number (42300286668).

Almost surely, 2141000955555 is an apocalyptic number.

141000955555 is a deficient number, since it is larger than the sum of its proper divisors (28200191117).

141000955555 is an equidigital number, since it uses as much as digits as its factorization.

141000955555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28200191116.

The product of its (nonzero) digits is 112500, while the sum is 40.

Adding to 141000955555 its reverse (555559000141), we get a palindrome (696559955696).

The spelling of 141000955555 in words is "one hundred forty-one billion, nine hundred fifty-five thousand, five hundred fifty-five".

Divisors: 1 5 28200191111 141000955555