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14100131113 = 73577334753
BaseRepresentation
bin11010010000110111…
…01110110100101001
31100101122212212122021
431020123232310221
5212334113143423
610251050424441
71006262064655
oct151033566451
940348785567
1014100131113
115a8617a222
122896132121
13143929a263
1497a8dda65
15577d1195d
hex3486eed29

14100131113 has 8 divisors (see below), whose sum is σ = 14318098088. Its totient is φ = 13882834944.

The previous prime is 14100131069. The next prime is 14100131119. The reversal of 14100131113 is 31113100141.

It can be written as a sum of positive squares in 4 ways, for example, as 10230917904 + 3869213209 = 101148^2 + 62203^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14100131113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14100131119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125256 + ... + 209497.

It is an arithmetic number, because the mean of its divisors is an integer number (1789762261).

Almost surely, 214100131113 is an apocalyptic number.

It is an amenable number.

14100131113 is a deficient number, since it is larger than the sum of its proper divisors (217966975).

14100131113 is an equidigital number, since it uses as much as digits as its factorization.

14100131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335403.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 14100131113 its reverse (31113100141), we get a palindrome (45213231254).

The spelling of 14100131113 in words is "fourteen billion, one hundred million, one hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 73 577 42121 334753 24436969 193152481 14100131113