14100364041401 has 4 divisors (see below), whose sum is σ = 15382215317904. Its totient is φ = 12818512764900.

The previous prime is 14100364041359. The next prime is 14100364041409. The reversal of 14100364041401 is 10414046300141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14100364041401 - 2³⁸ = 13825486134457 is a prime.

It is a super-2 number, since 2×14100364041401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14100364041409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640925638235 + ... + 640925638256.

It is an arithmetic number, because the mean of its divisors is an integer number (3845553829476).

Almost surely, 2^{14100364041401} is an apocalyptic number.

14100364041401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14100364041401 is a deficient number, since it is larger than the sum of its proper divisors (1281851276503).

14100364041401 is a wasteful number, since it uses less digits than its factorization.

14100364041401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1281851276502.

The product of its (nonzero) digits is 4608, while the sum is 29.

The spelling of 14100364041401 in words is "fourteen trillion, one hundred billion, three hundred sixty-four million, forty-one thousand, four hundred one".