14101000131 has 4 divisors (see below), whose sum is σ = 18801333512. Its totient is φ = 9400666752.

The previous prime is 14101000117. The next prime is 14101000159. The reversal of 14101000131 is 13100010141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14101000131 - 2⁵ = 14101000099 is a prime.

It is a super-3 number, since 3×14101000131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14101000231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350166686 + ... + 2350166691.

It is an arithmetic number, because the mean of its divisors is an integer number (4700333378).

Almost surely, 2^14101000131 is an apocalyptic number.

14101000131 is a deficient number, since it is larger than the sum of its proper divisors (4700333381).

14101000131 is an equidigital number, since it uses as much as digits as its factorization.

14101000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4700333380.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 14101000131 its reverse (13100010141), we get a palindrome (27201010272).

The spelling of 14101000131 in words is "fourteen billion, one hundred one million, one hundred thirty-one", and thus it is an aban number.