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141013001 = 824317107
BaseRepresentation
bin10000110011110…
…11000000001001
3100211100012110202
420121323000021
5242044404001
621554221545
73331406423
oct1031730011
9324305422
10141013001
1172664178
123b2848b5
13232a345c
1414a29813
15c5a696b
hex867b009

141013001 has 4 divisors (see below), whose sum is σ = 141038352. Its totient is φ = 140987652.

The previous prime is 141012997. The next prime is 141013021. The reversal of 141013001 is 100310141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141013001 - 22 = 141012997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141013021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311 + ... + 16796.

It is an arithmetic number, because the mean of its divisors is an integer number (35259588).

Almost surely, 2141013001 is an apocalyptic number.

It is an amenable number.

141013001 is a deficient number, since it is larger than the sum of its proper divisors (25351).

141013001 is an equidigital number, since it uses as much as digits as its factorization.

141013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25350.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 141013001 is about 11874.8895152755. The cubic root of 141013001 is about 520.4987830031.

Adding to 141013001 its reverse (100310141), we get a palindrome (241323142).

The spelling of 141013001 in words is "one hundred forty-one million, thirteen thousand, one".

Divisors: 1 8243 17107 141013001