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141013433 = 1112819403
BaseRepresentation
bin10000110011110…
…11000110111001
3100211100020001202
420121323012321
5242044412213
621554223545
73331410611
oct1031730671
9324306052
10141013433
1172664530
123b284bb5
13232a3702
1414a29a41
15c5a6b58
hex867b1b9

141013433 has 4 divisors (see below), whose sum is σ = 153832848. Its totient is φ = 128194020.

The previous prime is 141013429. The next prime is 141013441. The reversal of 141013433 is 334310141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141013433 - 22 = 141013429 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141013423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6409691 + ... + 6409712.

It is an arithmetic number, because the mean of its divisors is an integer number (38458212).

Almost surely, 2141013433 is an apocalyptic number.

It is an amenable number.

141013433 is a deficient number, since it is larger than the sum of its proper divisors (12819415).

141013433 is a wasteful number, since it uses less digits than its factorization.

141013433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12819414.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 141013433 is about 11874.9077049045. The cubic root of 141013433 is about 520.4993145268.

Adding to 141013433 its reverse (334310141), we get a palindrome (475323574).

The spelling of 141013433 in words is "one hundred forty-one million, thirteen thousand, four hundred thirty-three".

Divisors: 1 11 12819403 141013433