14102256601241 has 4 divisors (see below), whose sum is σ = 14102268906084. Its totient is φ = 14102244296400.

The previous prime is 14102256601207. The next prime is 14102256601297. The reversal of 14102256601241 is 14210665220141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7293267366025 + 6808989235216 = 2700605^2 + 2609404^2 .

It is a cyclic number.

It is not a de Polignac number, because 14102256601241 - 2⁴² = 9704210090137 is a prime.

It is a super-3 number, since 3×14102256601241³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14102256681241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4233890 + ... + 6791931.

It is an arithmetic number, because the mean of its divisors is an integer number (3525567226521).

Almost surely, 2^{14102256601241} is an apocalyptic number.

It is an amenable number.

14102256601241 is a deficient number, since it is larger than the sum of its proper divisors (12304843).

14102256601241 is a wasteful number, since it uses less digits than its factorization.

14102256601241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12304842.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 14102256601241 in words is "fourteen trillion, one hundred two billion, two hundred fifty-six million, six hundred one thousand, two hundred forty-one".