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141024313201 = 1271110427663
BaseRepresentation
bin1000001101010110110…
…1000011111101110001
3111111000020010101022011
42003111231003331301
54302304211010301
6144441412242521
713121466612112
oct2032555037561
9444006111264
10141024313201
1154898603882
12233b8910441
13103b5b62895
146b7b6a8209
153a05b06a51
hex20d5b43f71

141024313201 has 4 divisors (see below), whose sum is σ = 142134740992. Its totient is φ = 139913885412.

The previous prime is 141024313193. The next prime is 141024313219. The reversal of 141024313201 is 102313420141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141024313201 - 23 = 141024313193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141024313271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555213705 + ... + 555213958.

It is an arithmetic number, because the mean of its divisors is an integer number (35533685248).

Almost surely, 2141024313201 is an apocalyptic number.

It is an amenable number.

141024313201 is a deficient number, since it is larger than the sum of its proper divisors (1110427791).

141024313201 is a wasteful number, since it uses less digits than its factorization.

141024313201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1110427790.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 141024313201 its reverse (102313420141), we get a palindrome (243337733342).

The spelling of 141024313201 in words is "one hundred forty-one billion, twenty-four million, three hundred thirteen thousand, two hundred one".

Divisors: 1 127 1110427663 141024313201