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14103010330041 = 38095810881883
BaseRepresentation
bin1100110100111001110011…
…1010111100010110111001
31211221020100001000220111110
43031032130322330112321
53322030431121030131
645554500011550533
72653623512614353
oct315163472742671
954836301026443
1014103010330041
114548064737256
1216b931175b449
137b3ba6323a69
1436a8372240d3
15196cb956c646
hexcd39cebc5b9

14103010330041 has 8 divisors (see below), whose sum is σ = 18827257304160. Its totient is φ = 9390385121312.

The previous prime is 14103010330009. The next prime is 14103010330093. The reversal of 14103010330041 is 14003301030141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14103010330041 - 25 = 14103010330009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14103010337041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2905438515 + ... + 2905443368.

It is an arithmetic number, because the mean of its divisors is an integer number (2353407163020).

Almost surely, 214103010330041 is an apocalyptic number.

It is an amenable number.

14103010330041 is a deficient number, since it is larger than the sum of its proper divisors (4724246974119).

14103010330041 is an equidigital number, since it uses as much as digits as its factorization.

14103010330041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5810882695.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14103010330041 its reverse (14003301030141), we get a palindrome (28106311360182).

The spelling of 14103010330041 in words is "fourteen trillion, one hundred three billion, ten million, three hundred thirty thousand, forty-one".

Divisors: 1 3 809 2427 5810881883 17432645649 4701003443347 14103010330041