Base | Representation |
---|---|
bin | 1100110100111001110110… |
… | …0100011010001010000001 |
3 | 1211221020100210111011021120 |
4 | 3031032131210122022001 |
5 | 3322030441411400001 |
6 | 45554501040542453 |
7 | 2653624004166246 |
oct | 315163544321201 |
9 | 54836323434246 |
10 | 14103021200001 |
11 | 454806a890a98 |
12 | 16b9315321a29 |
13 | 7b3ba865b5a6 |
14 | 36a8388535cd |
15 | 196cba4b8236 |
hex | cd39d91a281 |
14103021200001 has 16 divisors (see below), whose sum is σ = 19978100319744. Its totient is φ = 8818753259264.
The previous prime is 14103021199999. The next prime is 14103021200029. The reversal of 14103021200001 is 10000212030141.
It is a cyclic number.
It is not a de Polignac number, because 14103021200001 - 21 = 14103021199999 is a prime.
It is a super-3 number, since 3×141030212000013 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (14103021210001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 471878961 + ... + 471908846.
It is an arithmetic number, because the mean of its divisors is an integer number (1248631269984).
Almost surely, 214103021200001 is an apocalyptic number.
It is an amenable number.
14103021200001 is a deficient number, since it is larger than the sum of its proper divisors (5875079119743).
14103021200001 is a wasteful number, since it uses less digits than its factorization.
14103021200001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 943788120.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 14103021200001 its reverse (10000212030141), we get a palindrome (24103233230142).
The spelling of 14103021200001 in words is "fourteen trillion, one hundred three billion, twenty-one million, two hundred thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •