Base | Representation |
---|---|
bin | 1000001101011000010… |
… | …0010010110100000011 |
3 | 111111000122120210101112 |
4 | 2003112010102310003 |
5 | 4302312240401311 |
6 | 144442150553535 |
7 | 13121602435436 |
oct | 2032604226403 |
9 | 444018523345 |
10 | 141030403331 |
11 | 548a0a93444 |
12 | 233ba9688ab |
13 | 103b71b58cc |
14 | 6b7c41181d |
15 | 3a0640b28b |
hex | 20d6112d03 |
141030403331 has 8 divisors (see below), whose sum is σ = 144083261184. Its totient is φ = 138005425800.
The previous prime is 141030403301. The next prime is 141030403337. The reversal of 141030403331 is 133304030141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 141030403331 - 226 = 140963294467 is a prime.
It is a super-2 number, since 2×1410304033312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141030403297 and 141030403306.
It is not an unprimeable number, because it can be changed into a prime (141030403337) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6959855 + ... + 6980088.
It is an arithmetic number, because the mean of its divisors is an integer number (18010407648).
Almost surely, 2141030403331 is an apocalyptic number.
141030403331 is a deficient number, since it is larger than the sum of its proper divisors (3052857853).
141030403331 is a wasteful number, since it uses less digits than its factorization.
141030403331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13940161.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 141030403331 its reverse (133304030141), we get a palindrome (274334433472).
The spelling of 141030403331 in words is "one hundred forty-one billion, thirty million, four hundred three thousand, three hundred thirty-one".
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