Base | Representation |
---|---|
bin | 11010010001001111… |
… | …10100110100111001 |
3 | 1100101212211221111112 |
4 | 31020213310310321 |
5 | 212340421121213 |
6 | 10251242410105 |
7 | 1006331040614 |
oct | 151047646471 |
9 | 40355757445 |
10 | 14103301433 |
11 | 5a87a45121 |
12 | 2897200935 |
13 | 1439b3a2a0 |
14 | 97b0c717b |
15 | 57823aea8 |
hex | 3489f4d39 |
14103301433 has 16 divisors (see below), whose sum is σ = 15605943360. Its totient is φ = 12660670656.
The previous prime is 14103301427. The next prime is 14103301451. The reversal of 14103301433 is 33410330141.
It is not a de Polignac number, because 14103301433 - 216 = 14103235897 is a prime.
It is a super-2 number, since 2×141033014332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14103301399 and 14103301408.
It is not an unprimeable number, because it can be changed into a prime (14103301403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1273466 + ... + 1284492.
It is an arithmetic number, because the mean of its divisors is an integer number (975371460).
Almost surely, 214103301433 is an apocalyptic number.
14103301433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
14103301433 is a deficient number, since it is larger than the sum of its proper divisors (1502641927).
14103301433 is a wasteful number, since it uses less digits than its factorization.
14103301433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13736.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 14103301433 its reverse (33410330141), we get a palindrome (47513631574).
The spelling of 14103301433 in words is "fourteen billion, one hundred three million, three hundred one thousand, four hundred thirty-three".
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