Base | Representation |
---|---|
bin | 1000001101011001011… |
… | …0011101001100100011 |
3 | 111111000222112200102022 |
4 | 2003112112131030203 |
5 | 4302320000230301 |
6 | 144442441012055 |
7 | 13121661055316 |
oct | 2032626351443 |
9 | 444028480368 |
10 | 141035164451 |
11 | 548a3745555 |
12 | 2340048402b |
13 | 103b8191a3c |
14 | 6b7ccd097d |
15 | 3a06a4bd1b |
hex | 20d659d323 |
141035164451 has 4 divisors (see below), whose sum is σ = 141329601600. Its totient is φ = 140740727304.
The previous prime is 141035164411. The next prime is 141035164471. The reversal of 141035164451 is 154461530141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141035164451 is a prime.
It is a super-2 number, since 2×1410351644512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141035164411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147217856 + ... + 147218813.
It is an arithmetic number, because the mean of its divisors is an integer number (35332400400).
Almost surely, 2141035164451 is an apocalyptic number.
141035164451 is a deficient number, since it is larger than the sum of its proper divisors (294437149).
141035164451 is an equidigital number, since it uses as much as digits as its factorization.
141035164451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294437148.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 141035164451 its reverse (154461530141), we get a palindrome (295496694592).
The spelling of 141035164451 in words is "one hundred forty-one billion, thirty-five million, one hundred sixty-four thousand, four hundred fifty-one".
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