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141035164451 = 479294436669
BaseRepresentation
bin1000001101011001011…
…0011101001100100011
3111111000222112200102022
42003112112131030203
54302320000230301
6144442441012055
713121661055316
oct2032626351443
9444028480368
10141035164451
11548a3745555
122340048402b
13103b8191a3c
146b7ccd097d
153a06a4bd1b
hex20d659d323

141035164451 has 4 divisors (see below), whose sum is σ = 141329601600. Its totient is φ = 140740727304.

The previous prime is 141035164411. The next prime is 141035164471. The reversal of 141035164451 is 154461530141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141035164451 is a prime.

It is a super-2 number, since 2×1410351644512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141035164411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147217856 + ... + 147218813.

It is an arithmetic number, because the mean of its divisors is an integer number (35332400400).

Almost surely, 2141035164451 is an apocalyptic number.

141035164451 is a deficient number, since it is larger than the sum of its proper divisors (294437149).

141035164451 is an equidigital number, since it uses as much as digits as its factorization.

141035164451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 294437148.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 141035164451 its reverse (154461530141), we get a palindrome (295496694592).

The spelling of 141035164451 in words is "one hundred forty-one billion, thirty-five million, one hundred sixty-four thousand, four hundred fifty-one".

Divisors: 1 479 294436669 141035164451