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141054342555 = 3571343374691
BaseRepresentation
bin1000001101011101111…
…1100111010110011011
3111111002022122000211110
42003113133213112123
54302334402430210
6144444404031403
713122313062210
oct2032737472633
9444068560743
10141054342555
1154903554325
1223406992563
13103bc148029
146b81683b07
153a08589420
hex20d77e759b

141054342555 has 16 divisors (see below), whose sum is σ = 257927940864. Its totient is φ = 64481985120.

The previous prime is 141054342479. The next prime is 141054342557. The reversal of 141054342555 is 555243450141.

It is not a de Polignac number, because 141054342555 - 213 = 141054334363 is a prime.

It is not an unprimeable number, because it can be changed into a prime (141054342557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 671687241 + ... + 671687450.

It is an arithmetic number, because the mean of its divisors is an integer number (16120496304).

Almost surely, 2141054342555 is an apocalyptic number.

141054342555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

141054342555 is a deficient number, since it is larger than the sum of its proper divisors (116873598309).

141054342555 is a wasteful number, since it uses less digits than its factorization.

141054342555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1343374706.

The product of its (nonzero) digits is 240000, while the sum is 39.

Adding to 141054342555 its reverse (555243450141), we get a palindrome (696297792696).

The spelling of 141054342555 in words is "one hundred forty-one billion, fifty-four million, three hundred forty-two thousand, five hundred fifty-five".

Divisors: 1 3 5 7 15 21 35 105 1343374691 4030124073 6716873455 9403622837 20150620365 28210868511 47018114185 141054342555