Base | Representation |
---|---|
bin | 1000001101101000111… |
… | …1011101101101010011 |
3 | 111111012112101001012011 |
4 | 2003122033131231103 |
5 | 4302433203043103 |
6 | 144453132043351 |
7 | 13123412645236 |
oct | 2033217355523 |
9 | 444175331164 |
10 | 141100440403 |
11 | 5492757a31a |
12 | 2341a303557 |
13 | 103c8868270 |
14 | 6b8784341d |
15 | 3a0c642d6d |
hex | 20da3ddb53 |
141100440403 has 8 divisors (see below), whose sum is σ = 151967759888. Its totient is φ = 130235040864.
The previous prime is 141100440401. The next prime is 141100440409. The reversal of 141100440403 is 304044001141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 141100440403 - 21 = 141100440401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141100440401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 325500 + ... + 623017.
It is an arithmetic number, because the mean of its divisors is an integer number (18995969986).
Almost surely, 2141100440403 is an apocalyptic number.
141100440403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
141100440403 is a deficient number, since it is larger than the sum of its proper divisors (10867319485).
141100440403 is a wasteful number, since it uses less digits than its factorization.
141100440403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 959973.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 141100440403 its reverse (304044001141), we get a palindrome (445144441544).
The spelling of 141100440403 in words is "one hundred forty-one billion, one hundred million, four hundred forty thousand, four hundred three".
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