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141100440403 = 1311443948517
BaseRepresentation
bin1000001101101000111…
…1011101101101010011
3111111012112101001012011
42003122033131231103
54302433203043103
6144453132043351
713123412645236
oct2033217355523
9444175331164
10141100440403
115492757a31a
122341a303557
13103c8868270
146b8784341d
153a0c642d6d
hex20da3ddb53

141100440403 has 8 divisors (see below), whose sum is σ = 151967759888. Its totient is φ = 130235040864.

The previous prime is 141100440401. The next prime is 141100440409. The reversal of 141100440403 is 304044001141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141100440403 - 21 = 141100440401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141100440401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 325500 + ... + 623017.

It is an arithmetic number, because the mean of its divisors is an integer number (18995969986).

Almost surely, 2141100440403 is an apocalyptic number.

141100440403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

141100440403 is a deficient number, since it is larger than the sum of its proper divisors (10867319485).

141100440403 is a wasteful number, since it uses less digits than its factorization.

141100440403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 959973.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 141100440403 its reverse (304044001141), we get a palindrome (445144441544).

The spelling of 141100440403 in words is "one hundred forty-one billion, one hundred million, four hundred forty thousand, four hundred three".

Divisors: 1 13 11443 148759 948517 12330721 10853880031 141100440403