1411013100041 has 4 divisors (see below), whose sum is σ = 1411015651584. Its totient is φ = 1411010548500.

The previous prime is 1411013100023. The next prime is 1411013100053. The reversal of 1411013100041 is 1400013101141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411013100041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411013099992 and 1411013100019.

It is not an unprimeable number, because it can be changed into a prime (1411013100641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60185 + ... + 1680966.

It is an arithmetic number, because the mean of its divisors is an integer number (352753912896).

Almost surely, 2^{1411013100041} is an apocalyptic number.

It is an amenable number.

1411013100041 is a deficient number, since it is larger than the sum of its proper divisors (2551543).

1411013100041 is an equidigital number, since it uses as much as digits as its factorization.

1411013100041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2551542.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1411013100041 its reverse (1400013101141), we get a palindrome (2811026201182).

The spelling of 1411013100041 in words is "one trillion, four hundred eleven billion, thirteen million, one hundred thousand, forty-one".