14110214123 has 4 divisors (see below), whose sum is σ = 14112891288. Its totient is φ = 14107536960.

The previous prime is 14110214119. The next prime is 14110214269. The reversal of 14110214123 is 32141201141.

14110214123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32141201141 = 7 ⋅4591600163.

It is a cyclic number.

It is not a de Polignac number, because 14110214123 - 2² = 14110214119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14110214095 and 14110214104.

It is not an unprimeable number, because it can be changed into a prime (14110214423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1330661 + ... + 1341222.

It is an arithmetic number, because the mean of its divisors is an integer number (3528222822).

Almost surely, 2^14110214123 is an apocalyptic number.

14110214123 is a deficient number, since it is larger than the sum of its proper divisors (2677165).

14110214123 is an equidigital number, since it uses as much as digits as its factorization.

14110214123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2677164.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14110214123 its reverse (32141201141), we get a palindrome (46251415264).

The spelling of 14110214123 in words is "fourteen billion, one hundred ten million, two hundred fourteen thousand, one hundred twenty-three".