14110221441 has 4 divisors (see below), whose sum is σ = 18813628592. Its totient is φ = 9406814292.

The previous prime is 14110221431. The next prime is 14110221451. The reversal of 14110221441 is 14412201141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (14110221431) and next prime (14110221451).

It is not a de Polignac number, because 14110221441 - 2⁵ = 14110221409 is a prime.

It is a super-2 number, since 2×14110221441² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14110221431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2351703571 + ... + 2351703576.

It is an arithmetic number, because the mean of its divisors is an integer number (4703407148).

Almost surely, 2^14110221441 is an apocalyptic number.

It is an amenable number.

14110221441 is a deficient number, since it is larger than the sum of its proper divisors (4703407151).

14110221441 is an equidigital number, since it uses as much as digits as its factorization.

14110221441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4703407150.

The product of its (nonzero) digits is 256, while the sum is 21.

Adding to 14110221441 its reverse (14412201141), we get a palindrome (28522422582).

The spelling of 14110221441 in words is "fourteen billion, one hundred ten million, two hundred twenty-one thousand, four hundred forty-one".