14111101010011 has 4 divisors (see below), whose sum is σ = 14111632308024. Its totient is φ = 14110569712000.

The previous prime is 14111101009877. The next prime is 14111101010059. The reversal of 14111101010011 is 11001010111141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14111101010011 - 2¹⁵ = 14111100977243 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14111101009973 and 14111101010000.

It is not an unprimeable number, because it can be changed into a prime (14111101010081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265609165 + ... + 265662286.

It is an arithmetic number, because the mean of its divisors is an integer number (3527908077006).

Almost surely, 2^{14111101010011} is an apocalyptic number.

14111101010011 is a deficient number, since it is larger than the sum of its proper divisors (531298013).

14111101010011 is an equidigital number, since it uses as much as digits as its factorization.

14111101010011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 531298012.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 14111101010011 its reverse (11001010111141), we get a palindrome (25112111121152).

The spelling of 14111101010011 in words is "fourteen trillion, one hundred eleven billion, one hundred one million, ten thousand, eleven".