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141111302200235 = 528222260440047
BaseRepresentation
bin100000000101011100001001…
…000010101001101110101011
3200111122002221021101120100122
4200011130021002221232223
5121443431421330401420
61220041345353553455
741502645421111523
oct4005341102515653
9614562837346318
10141111302200235
1140a64a70367594
12139b039571588b
13609797ac01703
1426bbb7584c683
15114a967322725
hex8057090a9bab

141111302200235 has 4 divisors (see below), whose sum is σ = 169333562640288. Its totient is φ = 112889041760184.

The previous prime is 141111302200213. The next prime is 141111302200241. The reversal of 141111302200235 is 532002203111141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141111302200235 - 210 = 141111302199211 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14111130220019 + ... + 14111130220028.

It is an arithmetic number, because the mean of its divisors is an integer number (42333390660072).

Almost surely, 2141111302200235 is an apocalyptic number.

141111302200235 is a deficient number, since it is larger than the sum of its proper divisors (28222260440053).

141111302200235 is an equidigital number, since it uses as much as digits as its factorization.

141111302200235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28222260440052.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 141111302200235 its reverse (532002203111141), we get a palindrome (673113505311376).

The spelling of 141111302200235 in words is "one hundred forty-one trillion, one hundred eleven billion, three hundred two million, two hundred thousand, two hundred thirty-five".

Divisors: 1 5 28222260440047 141111302200235