Base | Representation |
---|---|
bin | 100000000101011100001001… |
… | …000010101001101110101011 |
3 | 200111122002221021101120100122 |
4 | 200011130021002221232223 |
5 | 121443431421330401420 |
6 | 1220041345353553455 |
7 | 41502645421111523 |
oct | 4005341102515653 |
9 | 614562837346318 |
10 | 141111302200235 |
11 | 40a64a70367594 |
12 | 139b039571588b |
13 | 609797ac01703 |
14 | 26bbb7584c683 |
15 | 114a967322725 |
hex | 8057090a9bab |
141111302200235 has 4 divisors (see below), whose sum is σ = 169333562640288. Its totient is φ = 112889041760184.
The previous prime is 141111302200213. The next prime is 141111302200241. The reversal of 141111302200235 is 532002203111141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141111302200235 - 210 = 141111302199211 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14111130220019 + ... + 14111130220028.
It is an arithmetic number, because the mean of its divisors is an integer number (42333390660072).
Almost surely, 2141111302200235 is an apocalyptic number.
141111302200235 is a deficient number, since it is larger than the sum of its proper divisors (28222260440053).
141111302200235 is an equidigital number, since it uses as much as digits as its factorization.
141111302200235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28222260440052.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 141111302200235 its reverse (532002203111141), we get a palindrome (673113505311376).
The spelling of 141111302200235 in words is "one hundred forty-one trillion, one hundred eleven billion, three hundred two million, two hundred thousand, two hundred thirty-five".
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