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14111220001 = 43328167907
BaseRepresentation
bin11010010010001100…
…00010000100100001
31100102102202020201211
431021012002010201
5212344433020001
610252124230121
71006455251044
oct151106020441
940372666654
1014111220001
115a9146349a
12289999b341
13143b680628
1497c188c5b
15578ca2351
hex349182121

14111220001 has 4 divisors (see below), whose sum is σ = 14439387952. Its totient is φ = 13783052052.

The previous prime is 14111219999. The next prime is 14111220031. The reversal of 14111220001 is 10002211141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14111220001 - 21 = 14111219999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14111220031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164083911 + ... + 164083996.

It is an arithmetic number, because the mean of its divisors is an integer number (3609846988).

Almost surely, 214111220001 is an apocalyptic number.

It is an amenable number.

14111220001 is a deficient number, since it is larger than the sum of its proper divisors (328167951).

14111220001 is an equidigital number, since it uses as much as digits as its factorization.

14111220001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 328167950.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 14111220001 its reverse (10002211141), we get a palindrome (24113431142).

The spelling of 14111220001 in words is "fourteen billion, one hundred eleven million, two hundred twenty thousand, one".

Divisors: 1 43 328167907 14111220001