Base | Representation |
---|---|
bin | 100000000101011101101110… |
… | …110111011101111110001001 |
3 | 200111122021100022221110011020 |
4 | 200011131232313131332021 |
5 | 121443443421144411041 |
6 | 1220042231101423053 |
7 | 41503035643566231 |
oct | 4005355667357611 |
9 | 614567308843136 |
10 | 141113010544521 |
11 | 40a65767709974 |
12 | 139b079186aa89 |
13 | 6097b90b10012 |
14 | 26bbc986a6cc1 |
15 | 114aa172c3866 |
hex | 80576edddf89 |
141113010544521 has 8 divisors (see below), whose sum is σ = 188224784982240. Its totient is φ = 94038288234912.
The previous prime is 141113010544481. The next prime is 141113010544559. The reversal of 141113010544521 is 125445010311141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 141113010544521 - 234 = 141095830675337 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141113010544321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9263023140 + ... + 9263038373.
It is an arithmetic number, because the mean of its divisors is an integer number (23528098122780).
Almost surely, 2141113010544521 is an apocalyptic number.
It is an amenable number.
141113010544521 is a deficient number, since it is larger than the sum of its proper divisors (47111774437719).
141113010544521 is a wasteful number, since it uses less digits than its factorization.
141113010544521 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18526064055.
The product of its (nonzero) digits is 9600, while the sum is 33.
Adding to 141113010544521 its reverse (125445010311141), we get a palindrome (266558020855662).
The spelling of 141113010544521 in words is "one hundred forty-one trillion, one hundred thirteen billion, ten million, five hundred forty-four thousand, five hundred twenty-one".
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