Base | Representation |
---|---|
bin | 1000001101101100000… |
… | …0001000111000010001 |
3 | 111111020102101022021012 |
4 | 2003123000020320101 |
5 | 4302444434401040 |
6 | 144454305340305 |
7 | 13123626260531 |
oct | 2033300107021 |
9 | 444212338235 |
10 | 141113200145 |
11 | 549337a4965 |
12 | 23422637695 |
13 | 103cb3b4cc8 |
14 | 6b894054c1 |
15 | 3a0d813865 |
hex | 20db008e11 |
141113200145 has 8 divisors (see below), whose sum is σ = 172205939520. Its totient is φ = 110977160560.
The previous prime is 141113200141. The next prime is 141113200169. The reversal of 141113200145 is 541002311141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 141113200145 - 22 = 141113200141 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 141113200145.
It is not an unprimeable number, because it can be changed into a prime (141113200141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 239174621 + ... + 239175210.
It is an arithmetic number, because the mean of its divisors is an integer number (21525742440).
Almost surely, 2141113200145 is an apocalyptic number.
It is an amenable number.
141113200145 is a deficient number, since it is larger than the sum of its proper divisors (31092739375).
141113200145 is an equidigital number, since it uses as much as digits as its factorization.
141113200145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 478349895.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 141113200145 its reverse (541002311141), we get a palindrome (682115511286).
The spelling of 141113200145 in words is "one hundred forty-one billion, one hundred thirteen million, two hundred thousand, one hundred forty-five".
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