1411137753433 has 4 divisors (see below), whose sum is σ = 1413047277520. Its totient is φ = 1409228229348.

The previous prime is 1411137753413. The next prime is 1411137753439. The reversal of 1411137753433 is 3343577311141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411137753433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1411137753433.

It is not an unprimeable number, because it can be changed into a prime (1411137753439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 954760935 + ... + 954762412.

It is an arithmetic number, because the mean of its divisors is an integer number (353261819380).

Almost surely, 2^{1411137753433} is an apocalyptic number.

It is an amenable number.

1411137753433 is a deficient number, since it is larger than the sum of its proper divisors (1909524087).

1411137753433 is an equidigital number, since it uses as much as digits as its factorization.

1411137753433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1909524086.

The product of its digits is 317520, while the sum is 43.

The spelling of 1411137753433 in words is "one trillion, four hundred eleven billion, one hundred thirty-seven million, seven hundred fifty-three thousand, four hundred thirty-three".