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141115311553 = 311203453451
BaseRepresentation
bin1000001101101100100…
…0001100010111000001
3111111020120100120120111
42003123020030113001
54303001004432203
6144454422511321
713123653233326
oct2033310142701
9444216316514
10141115311553
1154934a07227
1223423295541
13103cb974068
146b897d4b4d
153a0dace26d
hex20db20c5c1

141115311553 has 4 divisors (see below), whose sum is σ = 141116076208. Its totient is φ = 141114546900.

The previous prime is 141115311479. The next prime is 141115311563. The reversal of 141115311553 is 355113511141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 141115311553 - 29 = 141115311041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141115311563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84478 + ... + 537928.

It is an arithmetic number, because the mean of its divisors is an integer number (35279019052).

Almost surely, 2141115311553 is an apocalyptic number.

It is an amenable number.

141115311553 is a deficient number, since it is larger than the sum of its proper divisors (764655).

141115311553 is an equidigital number, since it uses as much as digits as its factorization.

141115311553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 764654.

The product of its digits is 4500, while the sum is 31.

Adding to 141115311553 its reverse (355113511141), we get a palindrome (496228822694).

The spelling of 141115311553 in words is "one hundred forty-one billion, one hundred fifteen million, three hundred eleven thousand, five hundred fifty-three".

Divisors: 1 311203 453451 141115311553