Search a number
-
+
141120033 = 347040011
BaseRepresentation
bin10000110100101…
…01001000100001
3100211112122021220
420122111020201
5242111320113
622000405253
73332333445
oct1032251041
9324478256
10141120033
117272762a
123b316829
13233100a2
1414a56825
15c5c8523
hex8695221

141120033 has 4 divisors (see below), whose sum is σ = 188160048. Its totient is φ = 94080020.

The previous prime is 141120013. The next prime is 141120037. The reversal of 141120033 is 330021141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141120033 - 26 = 141119969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141119994 and 141120021.

It is not an unprimeable number, because it can be changed into a prime (141120037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520003 + ... + 23520008.

It is an arithmetic number, because the mean of its divisors is an integer number (47040012).

Almost surely, 2141120033 is an apocalyptic number.

It is an amenable number.

141120033 is a deficient number, since it is larger than the sum of its proper divisors (47040015).

141120033 is an equidigital number, since it uses as much as digits as its factorization.

141120033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47040014.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 141120033 is about 11879.3953128937. The cubic root of 141120033 is about 520.6304397445.

Adding to 141120033 its reverse (330021141), we get a palindrome (471141174).

The spelling of 141120033 in words is "one hundred forty-one million, one hundred twenty thousand, thirty-three".

Divisors: 1 3 47040011 141120033