Base | Representation |
---|---|
bin | 1000001101101101111… |
… | …0101111110101000011 |
3 | 111111020222110221221010 |
4 | 2003123132233311003 |
5 | 4303004013132003 |
6 | 144455153332003 |
7 | 13124054416644 |
oct | 2033336576503 |
9 | 444228427833 |
10 | 141121224003 |
11 | 54938285351 |
12 | 23425267003 |
13 | 103ccc64256 |
14 | 6b8a4d36cb |
15 | 3a0e39b003 |
hex | 20db7afd43 |
141121224003 has 4 divisors (see below), whose sum is σ = 188161632008. Its totient is φ = 94080816000.
The previous prime is 141121223989. The next prime is 141121224031. The reversal of 141121224003 is 300422121141.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 141121224003 - 213 = 141121215811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141121224043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520203998 + ... + 23520204003.
It is an arithmetic number, because the mean of its divisors is an integer number (47040408002).
Almost surely, 2141121224003 is an apocalyptic number.
141121224003 is a deficient number, since it is larger than the sum of its proper divisors (47040408005).
141121224003 is an equidigital number, since it uses as much as digits as its factorization.
141121224003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47040408004.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 141121224003 its reverse (300422121141), we get a palindrome (441543345144).
The spelling of 141121224003 in words is "one hundred forty-one billion, one hundred twenty-one million, two hundred twenty-four thousand, three".
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