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141121224011 = 433325915067
BaseRepresentation
bin1000001101101101111…
…0101111110101001011
3111111020222110221221102
42003123132233311023
54303004013132021
6144455153332015
713124054416655
oct2033336576513
9444228427842
10141121224011
1154938285359
122342526700b
13103ccc64261
146b8a4d36d5
153a0e39b00b
hex20db7afd4b

141121224011 has 4 divisors (see below), whose sum is σ = 141447139512. Its totient is φ = 140795308512.

The previous prime is 141121223989. The next prime is 141121224031. The reversal of 141121224011 is 110422121141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141121224011 - 222 = 141117029707 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141121224031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162957101 + ... + 162957966.

It is an arithmetic number, because the mean of its divisors is an integer number (35361784878).

Almost surely, 2141121224011 is an apocalyptic number.

141121224011 is a deficient number, since it is larger than the sum of its proper divisors (325915501).

141121224011 is an equidigital number, since it uses as much as digits as its factorization.

141121224011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 325915500.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 141121224011 its reverse (110422121141), we get a palindrome (251543345152).

The spelling of 141121224011 in words is "one hundred forty-one billion, one hundred twenty-one million, two hundred twenty-four thousand, eleven".

Divisors: 1 433 325915067 141121224011