141121334143201 has 4 divisors (see below), whose sum is σ = 141121418901552. Its totient is φ = 141121249384852.

The previous prime is 141121334143103. The next prime is 141121334143213. The reversal of 141121334143201 is 102341433121141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141121334143201 - 2¹⁷ = 141121334012129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141121334143271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39830611 + ... + 43228696.

It is an arithmetic number, because the mean of its divisors is an integer number (35280354725388).

Almost surely, 2^{141121334143201} is an apocalyptic number.

It is an amenable number.

141121334143201 is a deficient number, since it is larger than the sum of its proper divisors (84758351).

141121334143201 is an equidigital number, since it uses as much as digits as its factorization.

141121334143201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84758350.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 141121334143201 its reverse (102341433121141), we get a palindrome (243462767264342).

The spelling of 141121334143201 in words is "one hundred forty-one trillion, one hundred twenty-one billion, three hundred thirty-four million, one hundred forty-three thousand, two hundred one".