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141122113 = 1113992297
BaseRepresentation
bin10000110100101…
…01101001000001
3100211112202010221
420122111221001
5242111401423
622000423041
73332342506
oct1032255101
9324482127
10141122113
1172729150
123b317a81
1323311012
1414a574ad
15c5c8e5d
hex8695a41

141122113 has 8 divisors (see below), whose sum is σ = 155060640. Its totient is φ = 127368480.

The previous prime is 141122081. The next prime is 141122131. The reversal of 141122113 is 311221141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 141122113 - 25 = 141122081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141122413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44620 + ... + 47677.

It is an arithmetic number, because the mean of its divisors is an integer number (19382580).

Almost surely, 2141122113 is an apocalyptic number.

It is an amenable number.

141122113 is a deficient number, since it is larger than the sum of its proper divisors (13938527).

141122113 is a wasteful number, since it uses less digits than its factorization.

141122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92447.

The product of its digits is 48, while the sum is 16.

The square root of 141122113 is about 11879.4828591147. The cubic root of 141122113 is about 520.6329976285.

Adding to 141122113 its reverse (311221141), we get a palindrome (452343254).

It can be divided in two parts, 1 and 41122113, that added together give a palindrome (41122114).

The spelling of 141122113 in words is "one hundred forty-one million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 11 139 1529 92297 1015267 12829283 141122113