Base | Representation |
---|---|
bin | 11010010010010011… |
… | …10100001001100011 |
3 | 1100102111121121220001 |
4 | 31021021310021203 |
5 | 212400211232210 |
6 | 10252201400431 |
7 | 1006466550631 |
oct | 151111641143 |
9 | 40374547801 |
10 | 14112211555 |
11 | 5a91a80462 |
12 | 289a199117 |
13 | 143b939a50 |
14 | 97c366351 |
15 | 578deb03a |
hex | 349274263 |
14112211555 has 16 divisors (see below), whose sum is σ = 18349218720. Its totient is φ = 10357383168.
The previous prime is 14112211511. The next prime is 14112211559. The reversal of 14112211555 is 55511221141.
It is a cyclic number.
It is not a de Polignac number, because 14112211555 - 213 = 14112203363 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14112211559) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 655390 + ... + 676579.
It is an arithmetic number, because the mean of its divisors is an integer number (1146826170).
Almost surely, 214112211555 is an apocalyptic number.
14112211555 is a deficient number, since it is larger than the sum of its proper divisors (4237007165).
14112211555 is a wasteful number, since it uses less digits than its factorization.
14112211555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1332150.
The product of its digits is 2000, while the sum is 28.
Adding to 14112211555 its reverse (55511221141), we get a palindrome (69623432696).
The spelling of 14112211555 in words is "fourteen billion, one hundred twelve million, two hundred eleven thousand, five hundred fifty-five".
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