Base | Representation |
---|---|
bin | 10100100010010011010… |
… | …110011010111010011011 |
3 | 11222220121110001001010022 |
4 | 110202103112122322123 |
5 | 141110140134314433 |
6 | 3000150044141055 |
7 | 203646244663403 |
oct | 24422326327233 |
9 | 4886543031108 |
10 | 1411221401243 |
11 | 4a454a766115 |
12 | 1a960723778b |
13 | a310166c974 |
14 | 4c436a6d803 |
15 | 26a98384698 |
hex | 1489359ae9b |
1411221401243 has 4 divisors (see below), whose sum is σ = 1411251380760. Its totient is φ = 1411191421728.
The previous prime is 1411221401237. The next prime is 1411221401269. The reversal of 1411221401243 is 3421041221141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1411221401243 - 216 = 1411221335707 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1411221401203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14919038 + ... + 15013331.
It is an arithmetic number, because the mean of its divisors is an integer number (352812845190).
Almost surely, 21411221401243 is an apocalyptic number.
1411221401243 is a deficient number, since it is larger than the sum of its proper divisors (29979517).
1411221401243 is an equidigital number, since it uses as much as digits as its factorization.
1411221401243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29979516.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 1411221401243 its reverse (3421041221141), we get a palindrome (4832262622384).
The spelling of 1411221401243 in words is "one trillion, four hundred eleven billion, two hundred twenty-one million, four hundred one thousand, two hundred forty-three".
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