141122412141113 has 4 divisors (see below), whose sum is σ = 151977982305828. Its totient is φ = 130266841976400.

The previous prime is 141122412141107. The next prime is 141122412141149. The reversal of 141122412141113 is 311141214221141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11766182854969 + 129356229286144 = 3430187^2 + 11373488^2 .

It is a cyclic number.

It is not a de Polignac number, because 141122412141113 - 2¹⁰ = 141122412140089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141122412191113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5427785082338 + ... + 5427785082363.

It is an arithmetic number, because the mean of its divisors is an integer number (37994495576457).

Almost surely, 2^{141122412141113} is an apocalyptic number.

141122412141113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

141122412141113 is a deficient number, since it is larger than the sum of its proper divisors (10855570164715).

141122412141113 is a wasteful number, since it uses less digits than its factorization.

141122412141113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10855570164714.

The product of its digits is 1536, while the sum is 29.

Adding to 141122412141113 its reverse (311141214221141), we get a palindrome (452263626362254).

The spelling of 141122412141113 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred twelve million, one hundred forty-one thousand, one hundred thirteen".