14112433011 has 8 divisors (see below), whose sum is σ = 18832043664. Its totient is φ = 9400555520.

The previous prime is 14112433001. The next prime is 14112433061. The reversal of 14112433011 is 11033421141.

14112433011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14112433011 - 2⁶ = 14112432947 is a prime.

It is a super-2 number, since 2×14112433011² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14112433001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1929030 + ... + 1936331.

It is an arithmetic number, because the mean of its divisors is an integer number (2354005458).

Almost surely, 2^14112433011 is an apocalyptic number.

14112433011 is a deficient number, since it is larger than the sum of its proper divisors (4719610653).

14112433011 is a wasteful number, since it uses less digits than its factorization.

14112433011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3866581.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 14112433011 its reverse (11033421141), we get a palindrome (25145854152).

The spelling of 14112433011 in words is "fourteen billion, one hundred twelve million, four hundred thirty-three thousand, eleven".