Base | Representation |
---|---|
bin | 1100110101011101010101… |
… | …0000000110001100010011 |
3 | 1211222010221112211022000112 |
4 | 3031113111100012030103 |
5 | 3322204443101142120 |
6 | 50003114104111535 |
7 | 2654412013042001 |
oct | 315272520061423 |
9 | 54863845738015 |
10 | 14112545334035 |
11 | 4551107a22945 |
12 | 16bb132a655ab |
13 | 7b4a65893965 |
14 | 36b09d703a71 |
15 | 1971766c8bc5 |
hex | cd5d5406313 |
14112545334035 has 16 divisors (see below), whose sum is σ = 17068947111936. Its totient is φ = 11200780146528.
The previous prime is 14112545334023. The next prime is 14112545334037. The reversal of 14112545334035 is 53043354521141.
It is not a de Polignac number, because 14112545334035 - 226 = 14112478225171 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14112545333983 and 14112545334001.
It is not an unprimeable number, because it can be changed into a prime (14112545334037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20478242 + ... + 21156168.
It is an arithmetic number, because the mean of its divisors is an integer number (1066809194496).
Almost surely, 214112545334035 is an apocalyptic number.
14112545334035 is a deficient number, since it is larger than the sum of its proper divisors (2956401777901).
14112545334035 is a wasteful number, since it uses less digits than its factorization.
14112545334035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710842.
The product of its (nonzero) digits is 432000, while the sum is 41.
Adding to 14112545334035 its reverse (53043354521141), we get a palindrome (67155899855176).
The spelling of 14112545334035 in words is "fourteen trillion, one hundred twelve billion, five hundred forty-five million, three hundred thirty-four thousand, thirty-five".
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