141126035115131 has 4 divisors (see below), whose sum is σ = 153955674671064. Its totient is φ = 128296395559200.

The previous prime is 141126035115127. The next prime is 141126035115151. The reversal of 141126035115131 is 131511530621141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 141126035115131 - 2² = 141126035115127 is a prime.

It is a super-2 number, since 2×141126035115131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141126035115091 and 141126035115100.

It is not an unprimeable number, because it can be changed into a prime (141126035115151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6414819777950 + ... + 6414819777971.

It is an arithmetic number, because the mean of its divisors is an integer number (38488918667766).

Almost surely, 2^{141126035115131} is an apocalyptic number.

141126035115131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

141126035115131 is a deficient number, since it is larger than the sum of its proper divisors (12829639555933).

141126035115131 is a wasteful number, since it uses less digits than its factorization.

141126035115131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12829639555932.

The product of its (nonzero) digits is 10800, while the sum is 35.

Adding to 141126035115131 its reverse (131511530621141), we get a palindrome (272637565736272).

The spelling of 141126035115131 in words is "one hundred forty-one trillion, one hundred twenty-six billion, thirty-five million, one hundred fifteen thousand, one hundred thirty-one".