141131143144403 has 8 divisors (see below), whose sum is σ = 152574208805520. Its totient is φ = 130089588559200.

The previous prime is 141131143144351. The next prime is 141131143144417. The reversal of 141131143144403 is 304441341131141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141131143144403 - 2²⁶ = 141131076035539 is a prime.

It is a super-2 number, since 2×141131143144403² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (141131143144423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100377768248 + ... + 100377769653.

It is an arithmetic number, because the mean of its divisors is an integer number (19071776100690).

Almost surely, 2^{141131143144403} is an apocalyptic number.

141131143144403 is a deficient number, since it is larger than the sum of its proper divisors (11443065661117).

141131143144403 is a wasteful number, since it uses less digits than its factorization.

141131143144403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200755537957.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 141131143144403 its reverse (304441341131141), we get a palindrome (445572484275544).

The spelling of 141131143144403 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred forty-three million, one hundred forty-four thousand, four hundred three".