141131232214433 has 4 divisors (see below), whose sum is σ = 141133987820100. Its totient is φ = 141128476608768.

The previous prime is 141131232214409. The next prime is 141131232214447. The reversal of 141131232214433 is 334412232131141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 37665371132944 + 103465861081489 = 6137212^2 + 10171817^2 .

It is a cyclic number.

It is not a de Polignac number, because 141131232214433 - 2²⁴ = 141131215437217 is a prime.

It is a super-2 number, since 2×141131232214433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141131232214393 and 141131232214402.

It is not an unprimeable number, because it can be changed into a prime (141131232214493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1377726008 + ... + 1377828441.

It is an arithmetic number, because the mean of its divisors is an integer number (35283496955025).

Almost surely, 2^{141131232214433} is an apocalyptic number.

It is an amenable number.

141131232214433 is a deficient number, since it is larger than the sum of its proper divisors (2755605667).

141131232214433 is an equidigital number, since it uses as much as digits as its factorization.

141131232214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2755605666.

The product of its digits is 41472, while the sum is 35.

Adding to 141131232214433 its reverse (334412232131141), we get a palindrome (475543464345574).

The spelling of 141131232214433 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred thirty-two million, two hundred fourteen thousand, four hundred thirty-three".