14113135333201 has 4 divisors (see below), whose sum is σ = 14113164822372. Its totient is φ = 14113105844032.

The previous prime is 14113135333151. The next prime is 14113135333207. The reversal of 14113135333201 is 10233353131141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7002374440000 + 7110760893201 = 2646200^2 + 2666601^2 .

It is a cyclic number.

It is not a de Polignac number, because 14113135333201 - 2⁹ = 14113135332689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14113135333207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14014660 + ... + 14987893.

It is an arithmetic number, because the mean of its divisors is an integer number (3528291205593).

Almost surely, 2^{14113135333201} is an apocalyptic number.

It is an amenable number.

14113135333201 is a deficient number, since it is larger than the sum of its proper divisors (29489171).

14113135333201 is an equidigital number, since it uses as much as digits as its factorization.

14113135333201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29489170.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 14113135333201 its reverse (10233353131141), we get a palindrome (24346488464342).

The spelling of 14113135333201 in words is "fourteen trillion, one hundred thirteen billion, one hundred thirty-five million, three hundred thirty-three thousand, two hundred one".