14113143433 has 4 divisors (see below), whose sum is σ = 14494579780. Its totient is φ = 13731707088.

The previous prime is 14113143431. The next prime is 14113143449. The reversal of 14113143433 is 33434131141.

14113143433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33434131141 = 21221 ⋅1575521.

It can be written as a sum of positive squares in 2 ways, for example, as 7122009664 + 6991133769 = 84392^2 + 83613^2 .

It is a cyclic number.

It is not a de Polignac number, because 14113143433 - 2¹ = 14113143431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14113143431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190718118 + ... + 190718191.

It is an arithmetic number, because the mean of its divisors is an integer number (3623644945).

Almost surely, 2^14113143433 is an apocalyptic number.

It is an amenable number.

14113143433 is a deficient number, since it is larger than the sum of its proper divisors (381436347).

14113143433 is an equidigital number, since it uses as much as digits as its factorization.

14113143433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 381436346.

The product of its digits is 5184, while the sum is 28.

Adding to 14113143433 its reverse (33434131141), we get a palindrome (47547274574).

The spelling of 14113143433 in words is "fourteen billion, one hundred thirteen million, one hundred forty-three thousand, four hundred thirty-three".